Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
The roots of a quadratic equation are -3 and 1. Find its equation.
\(x^{2} - 3x + 1 = 0\)
\(x^{2} - 2x + 1 = 0\)
\(x^{2} + 2x - 3 = 0\)
\(x^{2} + x - 3 = 0\)
Correct answer is C
Given the roots of an equation such that you can find the sum and product of the roots, the equation can be given as:
\(x^{2} - (\alpha + \beta)x + (\alpha \beta) = 0 \)
\(\alpha + \beta = -3 + 1 = -2\)
\(\alpha \beta = -3 \times 1 = -3\)
Equation: \(x^{2} - (-2)x + (-3) = 0 \implies x^{2} + 2x - 3 = 0\)
\(q \implies p\)
\(\sim q \implies p\)
\(\sim q \implies \sim p\)
\(\sim p \implies \sim q\)
Correct answer is C
No explanation has been provided for this answer.
\(\frac{-5}{7}\)
\(-\frac{2}{5}\)
\(\frac{2}{5}\)
\(\frac{5}{7}\)
Correct answer is B
\(S_{\infty} = \frac{a}{1 - r}\) (Sum to infinity of a GP)
\(250 = \frac{350}{1 - r} \implies 250(1 - r) = 350\)
\(350 = 250 - 250r \implies 350 - 250 = -250r\)
\(250r = -100 \implies r = \frac{-100}{250} = -\frac{2}{5}\)
12.6 cm
12.0 cm
9.6 cm
9.0 cm
Correct answer is D
Length of arc (in radians) = \(r \theta\)
\(10.8 = 1.2r\)
\(r = \frac{10.8}{1.2} = 9.0 cm\)
The gradient of point P on the curve \(y = 3x^{2} - x + 3\) is 5. Find the coordinates of P.
(1, 5)
(1, 7)
(1, 13)
(1, 17)
Correct answer is A
\(y = 3x^{2} - x + 3\)
\(\frac{\mathrm d y}{\mathrm d x} = 6x - 1 = 5\)
\(6x = 5 + 1 = 6 \implies x = 1\)
\(y = 3(1^{2}) - 1 + 3 = 3 - 1 + 3 = 5\)
\(P = (1, 5)\)