Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Express the force F = (8 N, 150°) in the form (a i + b j) where a and b are constants
\(4\sqrt{3} i - 4j\)
\(4 i - 4\sqrt{3} j\)
\(- 4 i + 4\sqrt{3} j\)
\(- 4\sqrt{3} i + 4j\)
Correct answer is D
\(F = F\cos \theta i + F \sin \theta j\)
\((8 N, 150°) = 8 \cos 150 i + 8 \sin 150 j\)
= \(- 8 \cos 30 i + 8 \sin 30 j\)
= \(-8(\frac{\sqrt{3}}{2}) i + 8(\frac{1}{2} j\)
= \(-4\sqrt{3} i + 4 j\)
36 N
48 N
72 N
108 N
Correct answer is C
\(F = ma \)
\(a = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(F = 12(\frac{35 - 5}{5}) = 12 \times 6 = 72 N\)
\(\frac{5}{33}\)
\(\frac{13}{66}\)
\(\frac{8}{53}\)
\(\frac{19}{66}\)
Correct answer is D
\(P(\text{two same color balls}) = P(\text{2 red}) + P(\text{2 white}) + P(\text{2 black})\)
\(P(\text{2 red}) = \frac{3}{12} \times \frac{2}{11} = \frac{1}{22}\)
\(P(\text{2 white}) = \frac{4}{12} \times \frac{3}{11} = \frac{1}{11}\)
\(P(\text{2 black}) = \frac{5}{12} \times \frac{4}{11} = \frac{5}{33}\)
\(P(\text{2 same color balls}) = \frac{1}{22} + \frac{1}{11} + \frac{5}{33} = \frac{19}{66}\)
Eight football clubs are to play in a league on home and away basis. How many matches are possible?
14
28
56
128
Correct answer is C
Number of matches possible = \(2 \times ^{8}C_{2}\) (Home and away repitition of the matches)
= \(2 \times \frac{8!}{(8 - 2)! 2!}\)
= \(2 \times 28\)
= 56
If the mean of -1, 0, 9, 3, k, 5 is 2, where k is a constant, find the median of the set of numbers.
\(\frac{3}{2}\)
0
\(\frac{7}{2}\)
6
Correct answer is A
\(\frac{-1 + 0 + 9 + 3 + k + 5}{6} = 2 \implies 16 + k = 12\)
\(k = -4\)
Arranging -1, 0, 9, 3, -4, 5 in order: -4, -1, 0, 3, 5, 9
Median = \(\frac{0 + 3}{2} = \frac{3}{2}\)