x2−3x+2=0
x2−2x+3=0
x2−3x−2=0
x2−2x−3=0
Correct answer is A
Given ax2+bx+c=0(general form of a quadratic equation)
We have x2+bax+ca=0
x2−(−ba)x+ca=0
⟹x2−(α+β)x+(αβ)=0
∴
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