Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

216.

Find the coordinates of the point on the curve \(y = x^{2} + 4x - 2\), where the gradient is zero.

A.

(-2, 10)

B.

(-2, 2)

C.

(-2, -2)

D.

(-2, -6)

Correct answer is D

\(y = x^{2} + 4x - 2\)

\(\frac{\mathrm d y}{\mathrm d x} = 2x + 4 = 0\)

\(2x = -4 \implies x = -2\)

\(y(-2) = (-2^{2}) + 4(-2) - 2 = 4 - 8 - 2 = -6\)

\(\therefore (x, y) = (-2, -6)\)

217.

The equation of the line of best fit for variables x and y is \(y = 19.33 + 0.42x\), where x is the independent variable. Estimate the value of y when x = 15.

A.

18.91

B.

19.75

C.

25.63

D.

38.23

Correct answer is C

\(y = 19.33 + 0.42x\)

\(\text{The value of y when x = 15} = 19.33 + (0.42 \times 15)\)

= \(19.33 + 6.30\)

= 25.63

218.

In a firing contest, the probabilities that Kojo and Kwame hit the target are \(\frac{2}{5}\) and \(\frac{1}{3}\) respectively. What is the probability that none of them hit the target?

A.

\(\frac{1}{5}\)

B.

\(\frac{2}{5}\)

C.

\(\frac{3}{5}\)

D.

\(\frac{4}{5}\)

Correct answer is B

No explanation has been provided for this answer.

219.

Age(in years) 1 - 5 6 - 10 11 - 15
Frequency 3 5 2

Calculate the standard deviation of the distribution.

A.

1.10

B.

2.36

C.

3.50

D.

7.50

Correct answer is C

Age

(years)

Freq

(f)

Mid-value

(x)

fx \(d = (x - \bar{x})\) \(d^{2}\) \(fd^{2}\)
1 - 5 3 3 9 - 4.5 20.25 60.75
6 - 10 5 8 40 0.5 0.25 1.25
11 - 15 2 13 26 5.5 30.25 60.5
\(\sum =\) 10   75     122.5

\(Mean (\bar {x}) = \frac{\sum fx}{\sum f} = \frac{75}{10} = 7.5\)

\(SD = \sqrt{\frac{\sum fd^{2}}{\sum f}}\)

= \(\sqrt{\frac{122.5}{10}}\)

= \(\sqrt{12.25} = 3.50\)

220.

A particle of mass 2.5 kg is moving at a speed of 12 m/s. If a force of magnitude 10 N acts against it, find how long it takes to come to rest.

A.

1.5 s

B.

3.0 s

C.

4.0 s

D.

6.0 s

Correct answer is B

\(F = ma \)

\(10 = 2.5a \implies a = 4 ms^{-2}\)

Since it is a retarding movement, then \(a = -4 ms^{-2}\).

\(v = u + at; v = 0 ms^{-1}, u = 12 ms^{-1}\)

\(0 = 12 + (-4t) \implies 0 = 12 - 4t\)

\(4t = 12 \implies t = 3 s\)