Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
-49
-47
-10
-9
Correct answer is A
\(g : x \to 2x^{3}\)
\(g(-2) = 2(-2^{3}) = 2(-8) = -16\)
\(f : x \to 3x - 1\)
\(f(-16) = 3(-16) -1 = -48 - 1 = - 49\)
If \((x - 3)\) is a factor of \(2x^{3} + 3x^{2} - 17x - 30\), find the remaining factors.
(2x - 5)(x - 2)
(2x - 5)(x + 2)
(2x + 5)(x - 2)
(2x + 5)(x + 2)
Correct answer is D
Divide \(2x^{3} + 3x^{2} - 17x - 30\) by \((x - 3)\). You get \(2x^{2} + 9x + 10\).
Factorizing, we have \(2x^{2} + 9x + 10 = 2x^{2} + 4x + 5x + 10\)
\(2x(x + 2) + 5(x + 2)\)
= \((2x + 5)(x + 2)\)
\(\sqrt{3}\)
\(\frac{3\sqrt{2}}{4}\)
\(\frac{\sqrt{3}}{2}\)
\(\frac{\sqrt{2}}{2}\)
Correct answer is C
\(a ♦ b = \frac{ab}{4}\)
\(\sqrt{2} ♦ \sqrt{6} = \frac{\sqrt{2} \times \sqrt{6}}{4} = \frac{\sqrt{12}}{4}\)
= \(\frac{2\sqrt{3}}{4} \)
= \(\frac{\sqrt{3}}{2}\)
Simplify \(\sqrt{(\frac{-1}{64})^{\frac{-2}{3}}}\)
-4
\(-\frac{1}{4}\)
\(\frac{1}{8}\)
4
Correct answer is D
\((\frac{-1}{64})^{\frac{-2}{3}} = -64^{\frac{2}{3}}\)
\((-4^{3})^{\frac{2}{3}} = -4^{2} = 16\)
\(\therefore \sqrt{(\frac{-1}{64})^{\frac{-2}{3}} = \sqrt{16} = 4\)
Solve the inequality \(2x^{2} + 5x - 3 \geq 0\).
\(x \leq -3\) or \(x \geq \frac{1}{2}\)
\(x < -\frac{1}{2}\) or \(x \geq 3\)
\(-3 \leq x \leq \frac{1}{2}\)
\(-\frac{1}{2} \leq x \leq 3\)
Correct answer is A
No explanation has been provided for this answer.