| Age(in years) | 1 - 5 | 6 - 10 | 11 - 15 |
| Frequency | 3 | 5 | 2 |
Calculate the standard deviation of the distribution.
1.10
2.36
3.50
7.50
Correct answer is C
|
Age (years) |
Freq (f) |
Mid-value (x) |
fx | d=(x−ˉx) | d2 | fd2 |
| 1 - 5 | 3 | 3 | 9 | - 4.5 | 20.25 | 60.75 |
| 6 - 10 | 5 | 8 | 40 | 0.5 | 0.25 | 1.25 |
| 11 - 15 | 2 | 13 | 26 | 5.5 | 30.25 | 60.5 |
| ∑= | 10 | 75 | 122.5 |
Mean(ˉx)=∑fx∑f=7510=7.5
SD=√∑fd2∑f
= √122.510
= √12.25=3.50
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