Further Mathematics Questions and Answers
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
Solve: 8\(^{x - 2}\) = 4\(^{3x}\)
-2
-1
1
2
Correct answer is B
8\(^{x - 2}\) = 4\(^{3x}\)
2\(^{3(x - 2)}\) = 2\(^{2(3x)}\)
2 \(^{3x - 4}\) = 2\(^{6x}\)
2 \(^{x - 4}\) = 6\(^x\)
\(\frac{-4x}{-4}\) = \(\frac{4}{-4}\)
x = -1
14.11
13.81
12.06
11.05
Correct answer is C
No explanation has been provided for this answer.
16 N
\(16 \sqrt{3}\) N
18 N
\(18 \sqrt{3}\) N
Correct answer is B
No explanation has been provided for this answer.
1s
3s
7s
9s
Correct answer is D
No explanation has been provided for this answer.
Calculate, correct to one decimal place, the angle between 5i + 12j and -2i + 3j.
54.8°
56.3°
66.4°
76.3°
Correct answer is B
\(a . b = |a||b|\cos \theta\)
\((5i + 12j).(2i + 3j) = -10 + 36 = 26\)
\(26 = |5i + 12j||-2i + 3j|\cos \theta\)
\(|5i + 12j| = \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = 13\)
\(|2i + 3j| = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\)
\(26 = 13(\sqrt{13})\cos \theta\)
\(\cos \theta = \frac{26}{13\sqrt{13}} = 0.5547\)
\(\theta = 56.3°\)