-3 and 5
5 and -5
3 and -3
-5 and 3
Correct answer is D
Given an exponential sequence, say \(a, b, c,...\), as consecutive terms, then \(\sqrt{a \times c} = b\).
\(\therefore 2, (k+1), 8 \implies \sqrt{2 \times 8} = k + 1\)
\(k + 1 = \pm{4} \implies k = \text{-5 or 3}\)
Simplify \(2\log_{3} 8 - 3\log_{3} 2\)...
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