1 and -1
-1 and 2
1 and 2
0 and -1
Correct answer is D
√x+√x+1=√2x+1
Squaring both sides, we have
(√x+√x+1)2=(√2x+1)2
x+2√x(x+1)+x+1=2x+1
2x+1+2√x(x+1)−(2x+1)=0
(2√x(x+1))2=02⟹4(x(x+1))=0
∴
x = \text{0 or -1}
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