A binary operation * is defined on the set of real numbers, R, by
P * q = \(\frac{q^2 - p^2}{2pq}\). Find 3 * 2
\(\frac{13}{12}\)
\(\frac{5}{12}\)
-\(\frac{5}{12}\)
\(\frac{-1}{2}\)
Correct answer is C
P * q = \(\frac{q^2 - p^2}{2pq}\).
3 * 2 (where p = 3, q = 2)
i.e 3 *2 = \(\frac{3^2 - 2^2}{2 *3 * 2}\)
= \(\frac{4 - 9}{12}\)
= \(\frac{-5}{12}\)