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If y=1+x1x, find dydx....

If y=1+x1x, find dydx.

A.

2(1x)2

B.

2(1x)2

C.

11x

D.

11x

Correct answer is A

y=1+x1x

Using quotient rule, vdudxudvdxv2, we have

dydx=(1x)(1)(1+x)(1)(1x)2=(1x+1+x)(1x)2

= 2(1x)2.