6y - x - 29 = 0
6y + x - 31 = 0
y - 6x - 1 = 0
y - 6x + 1 = 0
Correct answer is B
y = 3x2+2
y1=dydx=6x
Evaluating this derivative at x = 1 (since the point of interest is (1, 5)) gives us the slope of the tangent line at that point:
mtangent=y1(1)=6(1)=6
Slope of the Normal Line mnormal=−1mtangent
mnormal=−16
y−y_1= ^mnormal⋅(x−x_1)
=y-5=-\frac{1}{6}(x-1)
=y-5=-\frac{1}{6}x+\frac{1}{6}
=y=-\frac{1}{6}x+\frac{1}{6}+5
Multiply through by 6
=6y=-x+1+30
∴6y+ x - 31=0
A body is acted upon by forces F_{1} = (10 N, 090°) and F_{2} = (6 N, 180°). Find th...
Find the coefficient of the 6^{th}term in the binomial expansion of \((1 - \frac{2x}{3})10\...
The angle subtended by an arc of a circle at the centre is \frac{\pi}{3} radians. If the radius ...
Find the fourth term of the binomial expansion of (x - k)^{5} in descending powers of x....
Given that \frac{2x}{(x + 6)(x + 3)} = \frac{P}{x + 6} + \frac{Q}{x + 3}, find P and Q....
Find the coordinates of the centre of the circle 3x^2 + 3y^2 - 6x + 9y - 5 = 0...
In how many ways can 8 persons be seated on a bench if only three seats are available? ...