Yomi was asked to label four seats S, R, P, Q. What is th...
Yomi was asked to label four seats S, R, P, Q. What is the probability he labelled them in alphabetical order?
\(\frac{1}{24}\)
\(\frac{1}{6}\)
\(\frac{2}{13}\)
\(\frac{1}{4}\)
Correct answer is A
The number of arrangements for the 4 letters = \(^{4}P_{4} = \frac{4!}{(4 - 4)!}\)
\(4! = 24\)
Alphabetical order is just 1 of the arrangements for the letters
= \(\frac{1}{24}\)
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