(-3. \(\frac{9}{2}\))
(-1. \(\frac{3}{2}\))
(1, - \(\frac{3}{2}\))
(3. -\(\frac{9}{2}\))
Correct answer is C
\(\frac{3x^2}{3} + \frac{3y^2}{3} - \frac{6x}{3} + \frac{9y}{3} - \frac{5}{3}\) = 0
2gx = -2x, 2 fy = 3y
g = -1, f = \(\frac{3}{2}\)
Centre (1, - \(\frac{3}{2}\))