−896x69
−896x59
−896x527
−896x627
Correct answer is C
rth term of a binomial expansion =nCr−1an−(r−1)br−1
n=10,r=6∴
6th term =^{10}C_5 1^{10} - 5 (-\frac{2}{3}x)^5
=252*1*-\frac{32x^5}{243}=-\frac{896x^5}{27}
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