\(4(6 + 5\pi)\)
\(4(6 + 2\pi)\)
\(4(3 + 3\pi)\)
\(4(3 + 5\pi)\)
Correct answer is A
The angle subtended by the minor arc = \(\frac{\pi}{3} radians\)
The angle subtended by the major arc = \(2\pi - \frac{\pi}{3} = \frac{5\pi}{3}\)
Perimeter of the major arc = \(r\theta + 2r\)
= \(12 \times \frac{5\pi}{3} + 2(12) = 20\pi + 24\)
= \(4(5\pi + 6)\)