(1, 2)
(1, -2)
(-1, 2)
(-1, -2)
Correct answer is A
4(2x2)=8x≡(22)(2x2)=(23)x
⟹22+x2=23x
Comparing bases, we have
2+x2=3x⟹x2−3x+2=0
x2−2x−x+2=0
x(x−2)−1(x−2)=0
(x−1)=0 or (x−2)=0
x=1 or 2
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