60º 0r 120º
30º 0r 150º
30º 0r 120º
60º 0r 150º
Correct answer is B
4sin\(^2\)θ + 1 = 2
4sin\(^2\)θ = 2 - 1
4sin\(^2\)θ = 1
\(\sqrt sin^2θ\) = \(\sqrt \frac{1}{4}\)
sinθ = \(\frac{1}{2}\)
θ = \(sin^{-1} \frac{1}{2}\)
θ = 30º 0r 150º
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