60º 0r 120º
30º 0r 150º
30º 0r 120º
60º 0r 150º
Correct answer is B
4sin2θ + 1 = 2
4sin2θ = 2 - 1
4sin2θ = 1
\sqrt sin^2θ = \sqrt \frac{1}{4}
sinθ = \frac{1}{2}
θ = sin^{-1} \frac{1}{2}
θ = 30º 0r 150º
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