y + 5x + 3 = 0
2y - 5x - 9 = 0
5y + 2x - 8 = 0
5y - 2x - 12 = 0
Correct answer is D
Line:2y+5x−6=0
2y=6−5x⟹y=3−5x2
Gradient = −52
For the line perpendicular to the given line, Gradient = −1−52=25
The midpoint of P(4, 3) and Q(-6, 1) = (−6+42,3+12)
= (-1, 2).
Therefore, the line = y−2x+1=25
2(x+1)=5(y−2)⟹5y−2x−12=0
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