The midpoint of M(4, -1) and N(x, y) is P(3, -4). Find the coordinates of N.
(2, -3)
(2, -7)
(-1, -3)
(-10, -7)
Correct answer is B
Given \(M(4, -1)\) and \(N(x, y)\) with midpoint \(P(3, -4)\).
\(\implies \frac{4 + x}{2} = 3; \frac{-1 + y}{2} = -4\)
\(\therefore x = 2; y = -7\)
N = (2, -7)