\(x = \frac{-41}{8}\)
\(x = \frac{-1}{4}\)
\(x = \frac{1}{4}\)
\(x = \frac{41}{8}\)
Correct answer is B
The line of symmetry of the curve is at the minimum point of the curve (ie y' = 0)
\(\frac{ \mathrm d}{ \mathrm d x} \left ( 5-x-2x^{2} \right)\) = -1 - 4x
If y' = 0, we have \(-1 - 4x = 0 \implies 4x = -1\)
\(x = \frac{-1}{4}\)