In the diagram, MN//PO, < PMN = 112o, < PNO = 129oo and < MPN = yo. Find the value of y
51o
54o
56o
68o
Correct answer is B
In \(\bigtriangleup\) NPO + PNO + PNO + < NOP = 180o(sum of interior angles of a \(\bigtriangleup\) )
i.e. NPO + 129 + 37 = 180
< NOP = 180 - (129 + 37) = 14o
< MNP = < NOP = 14o (alt. < s)
In \(\bigtriangleup\) MPN
< PMN + < MNP + y = 180(sum of interior angles of a \(\bigtriangleup\))
i.e. 112 + 14 + y = 180o
y = 180 - (112 + 14) = 180 - 126 = 54o
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