If x=y2,evaluate\(\left(\frac{x^{3}}{y^{3}...
If x=y2,evaluate(x3y3+12)÷(12−x2y2)
5/8
5/2
5/32
5/16
Correct answer is B
x=y2
(x3y3+12)÷(12−x2y2)
x3y3+12=(y2)3÷y3+12
= y38×1y3+12
= 18+12
= 58
12−x2y2=12−(y2)2÷y2)
= 12−y24×1y2
= 12−14
= 14
∴
= \frac{5}{2}
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