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If x=y2,evaluate\(\left(\frac{x^{3}}{y^{3}...

If x=y2,evaluate(x3y3+12)÷(12x2y2)

A.

5/8

B.

5/2

C.

5/32

D.

5/16

Correct answer is B

x=y2

(x3y3+12)÷(12x2y2)

x3y3+12=(y2)3÷y3+12

= y38×1y3+12

= 18+12

= 58

12x2y2=12(y2)2÷y2)

= 12y24×1y2

= 1214

= 14

= \frac{5}{2}