Each of the interior angles of a regular polygon is 140^o. Calculate the sum of all the interior angles of the polygon

1080^o

1260^o

1800^o

2160^o

Correct answer is B

Each interior angle = 140

\(\frac{(n - 2) \times 180}{n} = 140\)

(n - 2) x 180 = 140n

150 - 360 = 140n

180m - 140n = 360

40n - 360

n = \(\frac{360}{40}\)

n = 9

Sum of all interior angles = (n - 2) x 180

= (9 - 2) x 180

= 7 x 180

= 1260

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Each of the interior angles of a regular polygon is 140o. Calculate the sum of all the interior angles of the polygon

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Each of the interior angles of a regular polygon is 140^o. Calculate the sum of all the interior angles of the polygon