Alfred spent \(\frac{1}{4}\) of his money on food, \(\frac{1}{3}\) on clothing and save the rest. If he saved N72,20.00, how much did he spend on food?

A.

N43,200.00

B.

N43,000.00

C.

N42,200.00

D.

N40,000.00

Correct answer is A

let the total amount be Nx i.e (\(\frac{1}{4}\))x + (\(\frac{1}{3}\))x + 72,000 = x

\(\frac{x}{4} + \frac{x}{4} + 72,000 = x\)

\(\frac{3x + 4x + 86,400}{12} = x\)

cross multiply to clear fraction

12x = 3x + 4x + 86,400

12x - 7x = 86,400

5x = 86,400

x - \(\frac{86,400}{5}\) = 172,800

amount spent on food = \(\frac{1}{4} \times 172,800\)

= N43,200