\(\frac{3n}{2p^2}\)
\(\frac{2n}{3p^2}\)
\(\frac{2n}{3p}\)
\(\frac{3n^2}{2p^2}\)
Correct answer is A
M = \(\frac{nk}{p^2}\)
k → \(\frac{mp^2}{n}\) = \(\frac{3x1^2}{2}\)
k = \(\frac{3}{2}\)
: m = \(\frac{3xn}{2p^2}\)
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