Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

446.

The angle of a sector of a circle is 0.9 radians. If the radius of the circle is 4cm, find the length of the arc of the sector.

A.

3.6 cm

B.

7.6 cm

C.

8.0 cm

D.

11.6 cm

Correct answer is A

Length of arc given angle in radians = \(r \theta\)

= \(4 \times 0.9 = 3.6 cm\) 

447.

The distance s in metres covered by a particle in t seconds is \(s = \frac{3}{2}t^{2} - 3t\). Find its acceleration.

A.

\(1 ms^{-2}\)

B.

\(2 ms^{-2}\)

C.

\(3 ms^{-2}\)

D.

\(4 ms^{-2}\)

Correct answer is C

The two time differentiation of distance with respect to time will give the acceleration.

\(s = \frac{3}{2}t^{2} - 3t\)

\(\frac{\mathrm d s}{\mathrm d t} = v = 3t - 3\)

\(\frac{\mathrm d v}{\mathrm d t} = a = 3\)

448.

A box contains 4 red and 3 blue identical balls. If two are picked at random, one after the other without replacement, find the probability that one is red and the other is blue.

A.

\(\frac{4}{7}\)

B.

\(\frac{2}{7}\)

C.

\(\frac{1}{7}\)

D.

\(\frac{1}{12}\)

Correct answer is A

P(one blue, other red) = P(1st red then blue) or P(1st blue then red)

= \((\frac{4}{7} \times \frac{3}{6}) + (\frac{3}{7} \times \frac{4}{6})\)

= \(\frac{2}{7} + \frac{2}{7} = \frac{4}{7}\)

449.

Find the acute angle between the lines 2x + y = 4 and -3x + y + 7 = 0.

A.

40°

B.

44°

C.

45°

D.

54°

Correct answer is C

\(2x + y = 4 \equiv y = 4 - 2x \implies m_{1} = -2\)

\(-3x + y + 7 = 0 \equiv y = -7 + 3x \implies m_{2} = 3\)

\(\tan \theta = \frac{m_{1} - m_{2}}{1 - m_{1}m_{2}} = \frac{-2 - 3}{1 - (-2)(3)} = \frac{-5}{-5} = 1\)

\(\tan \theta = 1 \implies \theta = 45°\)

450.

Find the number of different arrangements of the word IKOTITINA.

A.

30240

B.

60840

C.

120960

D.

362880

Correct answer is A

IKOTITINA has 9 letters with 2Ts and 3Is. Therefore, the number of different arrangements

= \(\frac{9!}{2!3!} = \frac{9.8.7.6.5.4}{2} = 30240\)