Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

181.

A particle starts from rest and moves in a straight line such that its velocity, V ms\(^{-1}\), at time t second is given by V = 3t\(^2\) - 6t. Calculate the acceleration in the 3rd second. 

A.

12m

B.

16m

C.

64m

D.

96m

Correct answer is B

V = 3t\(^2\) - 6t

\(\frac{ds}{dt} = 3t^2 - 6t\)

s = \(\int 3t^2 - 6t\)

s = \(\frac{3t^3}{3} - \frac{6t^2}{2} + k\)

s = t\(^3\) - 3t\(^2\) + k

s = 0, t = 0

s = t\(^3\) - 3t\(^2\) 

s = 4\(^3\) - 3t\(^2\) 

s = 4\(^3\) - 3(4)\(^2\) 

= 64 - 48 = 16m

182.

Calculate the mean deviation of 5, 8, 2, 9 and 6

A.

5

B.

4

C.

3

D.

2

Correct answer is D

x x - \(\bar{x}\) (x - \(\bar{x}\))

5

8

2

9

6

-1

2

-4

3

0

1

2

4

3

0

 

\(\bar{x}\) = \(\frac{30}{5}\) = 6

\(\sum |x - \bar{x}|\)

= 10

Mean deviation = \(\frac{10}{5}\)

= 2

183.

If the mean of 2, 5, (x + 1), (x + 2), 7 and 9 is 6, find the median.

A.

6.5

B.

6.0

C.

5.5

D.

5.0

Correct answer is C

\(\frac{1 + 5 + x + 6 + x + 2 + 7 + 9}{6}\) = 6

26 + 2x = 36 

2x = 36 - 26

2x = 10 

x = \(\frac{10}{2}\) = 5

2, 5, 6, 7, 7, 9

Median = \(\frac{6 + 7}{2}\) = 6.5 

184.

Find the coordinates of the point in the curve y = 3x\(^2\) - 2x - 5 where the tangent is parallel to the line y = - 5 = 8x

A.

\(\begin{pmatrix} - \frac{5}{3} &, 0 \end {pmatrix}\)

B.

\(\begin{pmatrix} 0, & - \frac{5}{3} \end {pmatrix}\)

C.

\(\begin{pmatrix} 0, & \frac{5}{3} \end {pmatrix}\)

D.

\(\begin{pmatrix} \frac{5}{3} &, 0 \end {pmatrix}\)

Correct answer is D

y = 8x + 5 

m = 8

y = 3x\(^2\) - 2x - 5 

\(\frac{dy}{dx}\) = 6x - 2x - 5

\(\frac{6x}{6} = \frac{10}{6}\) 

x = \(\frac{5}{3}\)

y = 0