Further Mathematics questions and answers

Further Mathematics Questions and Answers

Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.

16.

In how many ways can a committee of 3 women and 2 men be chosen from a group of 7 men and 5 women?

A.

500

B.

350

C.

720

D.

210

Correct answer is D

For choosing, its different 'combinations'

Options - 7 men, 5 women
To pick - 2 men, 3 women

∴ The number of ways to choose a committee of 3 women and 2 men from a group of 7 men and 5 women is:
=\(^5C_3 \times ^7C_2\)

=\(\frac{5\times4\times3}{3\times2}\times\frac{7\times6}{2\times1}\)

=\(10\times21\)

=210

17.

Adu's scores in five subjects in an examination are 85848386 and 87. Calculate the standard deviation.

A.

2.0

B.

1.4

C.

1.8

D.

1.6

Correct answer is B

n = 5

x̄ = \(\frac{∑x}{n} = \frac{85 + 84 + 83 + 86 + 87}{5} = \frac{425}{5} = 85\)

\(x\)    \(x - x̄\)           \((x - x̄)^2\)
85   0                0
84  -1                1
83  -2                4
86   1                1
87   2                4
    \(\Sigma(x - x̄)^2 = 10\)

 

\(S.D = √\frac{∑(x - x̄ )}{n} = √\frac{10}{5}\)

∴ S.D = √2 =1.4

18.

An exponential sequence (G.P.) is given by \(\frac{9}{2},\frac{3}{4},\frac{1}{8},\)....Find its sum to infinity

A.

\(5\frac{2}{5}\)

B.

\(4\frac{1}{5}\)

C.

\(13\frac{1}{2}\)

D.

\(6\frac{3}{4}\)

Correct answer is A

Sum to infinity of a G.P when /r/ < 1 = \(\frac{a}{1 - r}\)

a = \(\frac{9}{2},r = \frac{T_2}{T_1} = \frac{3}{4} + \frac{9}{2}\)

r = \(\frac{3}{4} \times \frac{2}{9} = \frac{1}{6}\)

\(S_∞ = \frac{\frac{9}{2}}{1-\frac{1}{6}} = \frac{\frac{9}{2}}{\frac{5}{6}} = \frac{27}{5}\)

\(\therefore S_∞ = 5\frac{2}{5}\)

19.

A uniform beam PQ of length 80 cm and weight 60 N rests on a support at X where | PX | = 30 cm. If the body is kept in equilibrium by a mass m kg which is placed at P , calculate the value of m
[Take g = 10 ms\(^{-2}\)]

A.

2.0

B.

3.0

C.

2.5

D.

4.0

Correct answer is C

∑ clock wise moments =∑ anti clock wise moments

= 60 x 10 = 30 x m

= 600 = 30 m

m = \(\frac{600}{30} = 20 N\)

W = mg ==> m = \(\frac{W}{g}\)

∴ m = \(\frac{20}{10} = 2kg\)

20.

If \(f : x → 2 tan x\) and \(g : x → √(x^2 + 8), find ( g o f )(45^o)\)

A.

4

B.

2√3

C.

6

D.

3√2

Correct answer is B

\(f : x → 2 tan x\)

\(g : x → √(x^2 + 8)\)

\(( g o f ) = √((2 tan x)^2 + 8)\)

\(( g o f )(45º) = √((2 tan 45º)^2 + 8)\)

= √(4 + 8) = √12

= √(4 x 3)

∴ 2√3