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Find the coordinates of the point in the curve y = 3x2 ...

Find the coordinates of the point in the curve y = 3x2 - 2x - 5 where the tangent is parallel to the line y = - 5 = 8x

A.

(53,0)

B.

(0,53)

C.

(0,53)

D.

(53,0)

Correct answer is D

y = 8x + 5 

m = 8

y = 3x2 - 2x - 5 

dydx = 6x - 2x - 5

6x6=106 

x = 53

y = 0