A stone is thrown vertically upward and distance, S metre...
A stone is thrown vertically upward and distance, S metres after t seconds is given by S = 12t + 52t2 - t3.
Calculate the maximum height reached.
418.5m
56.0m
31.5m
30.0m
Correct answer is C
S = 12t + 52t2 - t3;
ds/dt = 12 + 5t - 3t2
At max height ds/dt = 0
i.e 12 + 5t - 3t2
(3t + 4)(t -3) = 0;
t = -4/3 or 3
Hmax = 12[3] + 52[3]2 - 33
= 36 + 45/2 - 27
= 31.5m
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