If √5 cosx + √15sinx = 0, for 0° < x &...
If √5 cosx + √15sinx = 0, for 0° < x < 360°, find the values of x.
30° and 150°
150° and 210°
150° and 330°
210° and 330°
Correct answer is C
√5 cosx + √15sinx = 0;
√5 (cosx + √3sinx) = 0
cosx = -sinx√3; sinxcos = −1√3
tanx = −1√3; x = 150° or 330°
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