0.7cm
1.2cm
2.0cm
2.5cm
Correct answer is B
let the chord be AB = 7cm
radius OA = 3.7cm distance of the = OM using Pythagoras theorem
OA2 = AM2 + OM2
3.72 = 3.52 + OM2
13.69 = 12.25 + OM2
13.69 - 12.25 = OM2
1.44 = OM2
OM = \(\sqrt{1.44}\)
OM = 1.2cm
distance of chord = 1.2cm
3.0cm
3.5cm
7.0cm
7.5cm
Correct answer is B
diameter = 12cm
radius = \(\frac{12}{2}\)cm = 6cm
area of sector = 66cm2
area of sector = area of cone
66 = \(\pi rl\)
66 = \(\frac{22}{7} \times r \times 6\)
divide both sides by 6
11 = \(\frac{22}{7}r\)
22r = 11 x 7
r = \(\frac{77}{22}\)
= 3.5cm
3.8
3.0
2.8
2.3
Correct answer is A
\(\begin{array}{c|c} height(x) & frequency(f) & fx \\ \hline 2 & 2 & 4\\ 3 & 4 & 12\\ 4 & 5 & 20 \\ 5 & 3 & 15\\ 6 & 1 & 6\end{array}\)
mean\(\bar{x} = \frac{\sum fx}{\sum f}\)
= \(\frac{57}{15}\)
= 3.8
If (x - a) is a factor pf bx - ax + x2, find the other factor.
(x + b)
(x - b)
(a + b)
(a - b)
Correct answer is A
No explanation has been provided for this answer.
Find the gradient of the line joining the points (2, -3) and 2, 5)
9
1
2
undefined
Correct answer is D
(2, -3)(2, 5)
gradient = \(\frac{y_ = y_1}{x_2 = x_1} = \frac{5 - (-3)}{2 - 2}\)
= \(\frac{5 + 3}{0}\)
= \(\frac{8}{0}\)
= undefined