3.8
3.0
2.8
2.3
Correct answer is A
\(\begin{array}{c|c} height(x) & frequency(f) & fx \\ \hline 2 & 2 & 4\\ 3 & 4 & 12\\ 4 & 5 & 20 \\ 5 & 3 & 15\\ 6 & 1 & 6\end{array}\)
mean\(\bar{x} = \frac{\sum fx}{\sum f}\)
= \(\frac{57}{15}\)
= 3.8
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