The following are scores obtained by some students in a test, Find the mode of the distribution
| 8 | 18 | 10 | 14 | 18 | 11 | 13 |
| 14 | 13 | 17 | 15 | 8 | 16 | 13 |
18
14
13
8
Correct answer is C
No explanation has been provided for this answer.
90
80
70
40
Correct answer is A
No of fruits = x
\(\frac{80}{360}\) x \(x\) = 60
x = \(\frac{60 \times 360}{80}\) x 270
= 90
\(\frac{1}{6}\)
\(\frac{1}{4}\)
\(\frac{1}{3}\)
\(\frac{1}{2}\)
Correct answer is C
Pr(green) = \(\frac{6}{5 + 6 + 7}\)
= \(\frac{6}{18}\)
= \(\frac{1}{3}\)
In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of n
40\(^o\)
55\(^o\)
75\(^o\)
130\(^o\)
Correct answer is C
E\(G\)R = 50\(^o\) (Alternative angles)
n + 55\(^o\) + 50\(^o\) = 180\(^o\) (Sum of angles on a straight line)
n = 180\(^o\) - 105\(^o\)
n = 75\(^o\)
In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of m.
130\(^o\)
105\(^o\)
75\(^o\)
55\(^o\)
Correct answer is D
50\(^o\) + m = 105\(^o\) (exterior angle of \(\triangle\)
m = 105\(^o\) - 50\(^o\)
m = 55\(^o\)
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