40\(^o\)
55\(^o\)
75\(^o\)
130\(^o\)
Correct answer is C
E\(G\)R = 50\(^o\) (Alternative angles)
n + 55\(^o\) + 50\(^o\) = 180\(^o\) (Sum of angles on a straight line)
n = 180\(^o\) - 105\(^o\)
n = 75\(^o\)
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