In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of n
A.
40\(^o\)
B.
55\(^o\)
C.
75\(^o\)
D.
130\(^o\)
Correct answer is C
E\(G\)R = 50\(^o\) (Alternative angles)
n + 55\(^o\) + 50\(^o\) = 180\(^o\) (Sum of angles on a straight line)
n = 180\(^o\) - 105\(^o\)
n = 75\(^o\)