In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of m.
A.
130\(^o\)
B.
105\(^o\)
C.
75\(^o\)
D.
55\(^o\)
Correct answer is D
50\(^o\) + m = 105\(^o\) (exterior angle of \(\triangle\)
m = 105\(^o\) - 50\(^o\)
m = 55\(^o\)