12m
16m
64m
96m
Correct answer is B
V = 3t\(^2\) - 6t
\(\frac{ds}{dt} = 3t^2 - 6t\)
s = \(\int 3t^2 - 6t\)
s = \(\frac{3t^3}{3} - \frac{6t^2}{2} + k\)
s = t\(^3\) - 3t\(^2\) + k
s = 0, t = 0
s = t\(^3\) - 3t\(^2\)
s = 4\(^3\) - 3t\(^2\)
s = 4\(^3\) - 3(4)\(^2\)
= 64 - 48 = 16m
Calculate the mean deviation of 5, 8, 2, 9 and 6
5
4
3
2
Correct answer is D
| x | x - \(\bar{x}\) | (x - \(\bar{x}\)) |
|
5 8 2 9 6 |
-1 2 -4 3 0 |
1 2 4 3 0 |
\(\bar{x}\) = \(\frac{30}{5}\) = 6
\(\sum |x - \bar{x}|\)
= 10
Mean deviation = \(\frac{10}{5}\)
= 2
If the mean of 2, 5, (x + 1), (x + 2), 7 and 9 is 6, find the median.
6.5
6.0
5.5
5.0
Correct answer is C
\(\frac{1 + 5 + x + 6 + x + 2 + 7 + 9}{6}\) = 6
26 + 2x = 36
2x = 36 - 26
2x = 10
x = \(\frac{10}{2}\) = 5
2, 5, 6, 7, 7, 9
Median = \(\frac{6 + 7}{2}\) = 6.5
\(\begin{pmatrix} - \frac{5}{3} &, 0 \end {pmatrix}\)
\(\begin{pmatrix} 0, & - \frac{5}{3} \end {pmatrix}\)
\(\begin{pmatrix} 0, & \frac{5}{3} \end {pmatrix}\)
\(\begin{pmatrix} \frac{5}{3} &, 0 \end {pmatrix}\)
Correct answer is D
y = 8x + 5
m = 8
y = 3x\(^2\) - 2x - 5
\(\frac{dy}{dx}\) = 6x - 2x - 5
\(\frac{6x}{6} = \frac{10}{6}\)
x = \(\frac{5}{3}\)
y = 0
30m
32m
42m
50m
Correct answer is B
h = 96 Tan 30\(^o\) = 55.425
P = \(\frac{55.425}{Tan60^o}\)
= 32m