Processing math: 75%

WAEC Mathematics Past Questions & Answers - Page 316

1,576.

Which triangle is equal in area to ΔVWZ

A.

ΔVXZ

B.

ΔVYZ

C.

ΔXYV

D.

ΔWYV

E.

ΔWYZ

Correct answer is B

Area of Δ VYZ = Area of Δ VWZ (same base and within same parallel)

1,577.

Which angle is equal to ∠VWZ?

A.

∠VXZ

B.

∠VYX

C.

∠XZW

D.

∠YXZ

E.

∠VYW

Correct answer is A

< VWZ = < VXZ (angles in the same segment)

1,578.

In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR

A.

5.12cm2

B.

9.60cm2

C.

10.24cm2

D.

20.48cm2

E.

40.96cm2

Correct answer is C

Area of a triangle = 12×b×h

Area of Δ SQR = 12×6.4×3.2

= 10.24 cm2

1,579.

In the diagram above, WXYZ is a rhombus and ∠WYX = 20°. What is the value of ∠XZY

A.

20o

B.

30o

C.

45o

D.

60o

E.

70o

Correct answer is E

Diagonals bisect at 90°;  < YXZ = 90° - 20° = 70°

But ZY = XY (sides of a rhombus)

< XYZ = 70° (base angle of an isos. triangle)

1,580.

In the diagram above, |PQ| = |PR| = |RS| and ∠RPS = 32°. Find the value of ∠QPR

A.

72o

B.

64o

C.

52o

D.

32o

E.

26o

Correct answer is C

From the figure, < PSR = 32° (base angles of an isos. triangle)

\therefore < PRS = 180° - (32° + 32°) = 116° (sum of angles in a triangle)

< QRP = 180° - 116° = 64° (angle on a straight line)

< PQR = 64° (base angles of an isos. triangle)

< QPR = 180° - (64° + 64°) = 52°