In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicul...
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR
5.12cm2
9.60cm2
10.24cm2
20.48cm2
40.96cm2
Correct answer is C
Area of a triangle = \(\frac{1}{2} \times b \times h\)
Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\)
= 10.24 cm\(^2\)
Similar Questions
lf \(log_q p= r\), express p in terms of q and r...
Simplify \(\frac{2\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}}\) ...
Find the value of t in the diagram above ...
If a{\(\frac{x + 1}{x - 2} - \frac{x - 1}{x + 2}\)} = 6x. Find a in its simplest form...
Factorize m3 - 2m2 - m + 2 ...
Simplify \(\frac{x - y}{x^{\frac{1}{3}} - x^{\frac{1}{3}}}\)...
Express 0.03785 in standard form correct to 3 significant figures. ...
A cuboid has a diagonal of length 9cm and a square base of side 4cm. What is its height? ...
Calculate (0.05 × 0.025) ÷ (4.25 × 3.35) and express your answer in standard form...