Which of the following is equal to \(\frac{72}{125}\)
\( \frac{2^3 \times 3^2}{5^3} \)
\( \frac{2^4 \times 3}{5^3} \)
\( \frac{2^3 \times 3}{5^3} \)
\( \frac{2^4 \times 3}{5^5} \)
\( \frac{2^2 \times 3^2 \times 4^2}{5^2} \)
Correct answer is A
\(\frac{72}{125} = \frac{8 \times 9}{5 \times 5 \times 5}\)
= \(\frac{2^3 \times 3^2}{5^3}\)
Simplify: \(2\frac{1}{3} \div 2\frac{2}{3} \times 1\frac{1}{7}\)
0
1
2
3
4
Correct answer is B
\(2\frac{1}{3} \div 2\frac{2}{3} \times 1\frac{1}{7}\)
= \(\frac{7}{3} \div \frac{8}{3} \times \frac{8}{7}\)
= \(\frac{7}{3} \times \frac{3}{8} \times \frac{8}{7}\)
= 1
| Number | 1 | 2 | 3 | 4 | 5 | 6 |
| No of times | 25 | 30 | 45 | 28 | 40 | 32 |
A die rolled 200 times. The outcome obtained are shown in the table above.
What is the probability of obtaining a number less than 3 ?
0.125
0.150
0.275
0.500
0.725
Correct answer is C
Prob(less than 3) = \(\frac{25 + 30}{200}\)
= \(\frac{11}{40}\)
= 0.275
0.002
0.015
0.15
16
0.2
Correct answer is C
Prob(obtaining a 2) = \(\frac{30}{200}\)
= \(0.15\)
What is the probability that the total sum of seven would appear in toss of a fair die?
5/36
1/6
7/36
5/6
1
Correct answer is B
No of possible outcome = 36
Required outcome (R) = {(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)}
n(R) = \(\frac{6}{36}\)
= \(\frac{1}{6}\)
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