What is the probability that the total sum of seven would appear in toss of a fair die?
5/36
1/6
7/36
5/6
1
Correct answer is B
No of possible outcome = 36
Required outcome (R) = {(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)}
n(R) = \(\frac{6}{36}\)
= \(\frac{1}{6}\)