A fair coin is tossed three times. Find the probability of getting two heads and one tail.
\(\frac{1}{2}\)
\(\frac{3}{8}\)
\(\frac{1}{4}\)
\(\frac{1}{8}\)
Correct answer is B
Pr(head) = \(\frac{1}{2}\), Pr(tail) = \(\frac{1}{2}\):Pr(2 heads)
= \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\)
Pr(2 heads and tail) 3 times
= (\(\frac{1}{4}\) x \(\frac{1}{2}\)) x 3
= \(\frac{3}{8}\)
a straight line joining A and P
the perpendicular bisector of AP
a circle with centre A
the triangle with centre P
Correct answer is C
No explanation has been provided for this answer.
Given that y = 1 - \(\frac{2x}{4x - 3}\), find the value of x for which y is undefined
3
\(\frac{3}{4}\)
\(\frac{-3}{4}\)
-3
Correct answer is B
for undefined expression, the denomination is zero 4x - 3 = 0
4x = 3; x = \(\frac{3}{4}\)
Simplify \(\frac{x - 4}{4} - \frac{x - 3}{6}\)
\(\frac{x - 18}{12}\)
\(\frac{x - 6}{12}\)
\(\frac{x - 18}{24}\)
\(\frac{x - 6}{24}\)
Correct answer is B
\(\frac{x - 4}{4} - \frac{x - 3}{6}\) = \(\frac{3(x - 4) - 2(x - 3)}{12}\)
= \(\frac{3x -12 - 2x + 6}{12}\)
= \(\frac{3x - 2x - 12 + 6}{12}\)
= \(\frac{x - 6}{12}\)
25
\(\frac{1}{5}\)
1
\(\frac{1}{25}\)
Correct answer is C
\(\frac{25 \frac{2}{3} \div 25 \frac{1}{6}}{( \frac{1}{5})^{-\frac{7}{6}} \times ( \frac{1}{5})^{\frac{1}{6}}}\) = \(\frac{25^{4 - \frac{1}{6}}}{(\frac{1}{5})^{-7 + \frac{1}{6}}}\)
= \(\frac{25^{\frac{1}{2}}}{(\frac{1}{5})^{-1}}\)
= \(\frac{(5^2)^{\frac{1}{2}}}{(5^{-1})^{-1}}\)
= \(\frac{5}{5}\)
= 1