Evaluate (0.13)3correct to three significant figures
0.00219
0.00220
0.00300
0.00390
Correct answer is B
(0.13)3 = 0.13 x 0.13 x 0.13 = 0.002197
= 0.00220 (3 s.f)
P=Q12R
P=12QR
P=12QR
P=12QR
Correct answer is B
P∝QR
P=KQR
When Q = 36, R = 16, P = 27
Then substitute into the equation
27=K3616
K=27×1636
K=12
So the equation connecting P, Q and R is
P=12QR
y varies directly as w2. When y = 8, w = 2. Find y when w = 3
18
12
9
6
Correct answer is A
y∝w2
y = kw2
8 = k(2)2
8 = k(4)
k = 8/4
k = 2
Thus y = 2w2
When w = 3, y = 2(3)2
y = 2 x 9 = 18
Find the value of k if y - 1 is a factor of y3 + 4y2 + ky - 6
-6
-4
0
1
Correct answer is D
if y - 1 is a factor of y3 + 4y2 + ky - 6, then
f(1) = (1)3 + 4(1)2 + k(1) - 6 = 0 (factor theorem)
1 + 4 + k - 6 = 0
5 - 6 + k = 0
-1 + k = 0
k = 1