-6
-4
0
1
Correct answer is D
if y - 1 is a factor of y3 + 4y2 + ky - 6, then f(1) = (1)3 + 4(1)2 + k(1) - 6 = 0 (factor theorem) 1 + 4 + k - 6 = 0 5 - 6 + k = 0 -1 + k = 0 k = 1
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