N80,000
N40,000
N2,000
10,000
Correct answer is B
Let Abu's share = 2x;
Kayode's = x
Uche's share = \(\frac{x}{2}\)
Total: 2x + x + \(\frac{x}{2}\) = N140,000
\(\frac{7x}{2}\) = N140,000
x = \(\frac{280,000}{7}\) = N40,000
Kayode's share = N40,000
Simplify \(\frac{3x^3}{(3x)^3}\)
1
\(\frac{1}{3}\)
\(\frac{1}{9}\)
\(\frac{1}{27}\)
Correct answer is C
\(\frac{3x^3}{(3x)^3}\) = \(\frac{3 \times x^3}{3^3 \times x^3}\)
= \(\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3}\)
= \(\frac{1}{3^2}\)
= \(\frac{1}{9}\)
least value of x is -3.2
least value of x is -3
greatest value of x is 4.9
greatest value of x is 5
Correct answer is B
p = {-3.2.....4.9}; Since x is an integer
least value of x is -3
Simplify 3\(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\), leaving your answer in surd form.
29\(\sqrt{5}\)
14\(\sqrt{15}\)
12\(\sqrt{15}\)
11\(\sqrt{15}\)
Correct answer is A
3 \(\sqrt{45} - 12\sqrt{5} + 16\sqrt{20}\)
= 3 x \(\sqrt{9 \times 5} - 12 \times \sqrt{5} + 16 \times \sqrt{4 \times 5}\)
= 3 x 3 x \(\sqrt{5} - 12 \times \sqrt{5} + 16 \times 2 \times \sqrt{5}\)
= 9\(\sqrt{5} - 2 \sqrt{5} + 32 \sqrt{5}\)
= 9\(\sqrt{5} + 32\sqrt{5} - 12\sqrt{5}\)
= 29\(\sqrt{5}\)
If p \(\alpha \frac{I}{Q}\) which of the following is true?
q \(\alpha p^2\)
q \(\alpha \frac{1}{p^2}\)
q \(\alpha \sqrt{p}\)
q \(\alpha \frac{1}{p}\)
Correct answer is D
p \(\alpha \frac{I}{Q}\); p \(\frac{k}{q}\) (where k is constant)
q = \(\frac{k}{p}\)
q \(\alpha \frac{1}{p}\)