1
\(\frac{1}{3}\)
\(\frac{1}{9}\)
\(\frac{1}{27}\)
Correct answer is C
\(\frac{3x^3}{(3x)^3}\) = \(\frac{3 \times x^3}{3^3 \times x^3}\) = \(\frac{3 \times x^3}{3 \times 3 \times 3 \times x^3}\) = \(\frac{1}{3^2}\) = \(\frac{1}{9}\)
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