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WAEC Mathematics Past Questions & Answers - Page 142

706.

If the perimeter of PQR in thr diagram is 24cm, what is the area of PRS?

A.

19.5cm2

B.

15.0cm2

C.

13.0cm2

D.

9.3cm2

Correct answer is B

Perimeter of PQR = PQ + QR + PR

24cm = 6cm + 8cm = PR

24 = 14 + PR

PR = 24 - 14 = 10cm

Area of PRS = 12×10×3cm3

= 15cm3

707.

In the diagram, O is the centre of the circle and PQRS is a cyclic quadrilateral. Find the value of x.

A.

25o

B.

65o

C.

115o

D.

130o

Correct answer is B

x = 65o (An interior angle of a cyclic quadrilateral = opposite exterior angle).

708.

In the figure /PX/ = /XQ/, PQ//YZ and XV//QR. What is the ratio of the area of XYZQ to te area of YZR?

A.

1:2

B.

2:1

C.

1:2

D.

3:1

Correct answer is B

From the diagram, XYZQ is a parallelogram. Thus, |YZ| = |XQ| = |PX|; PXY, Let the area of XYZQ = A1, the area of PXY

= Area of YZR = A2

Area of PQR = A = A1 + 2A2

But from similarity of triangles

Area of PQRArea of PXY=(PQPX)2=(QRXY)2

AA2=(21)2=21

A = 4A2 But, A = A1 + 2A

A1 = 4A2 - 2A2

A1 = 2A2

A1A2 = 2

A1:A2 = 2:1


Area of XYZQ:Area of YZR = 2:1

709.

In the diagram, PQ//RS, QU//PT and < PSR = 42o. Find angle x.

A.

84o

B.

48o

C.

42o

D.

32o

Correct answer is C

From the diagram, < QPS = xo (Corresponding angles)

Also, < QPS = < PSR(Alternate angles)

x = 42o

710.

In the figure shown, PQs is a straight line. What is the value of < PRQ?

A.

128o

B.

108o

C.

98o

D.

78o

Correct answer is D

< QPR + < PRQ = < RQS

(Sum of two interior angles of a triangle = Opposite exterior angles)

70o + < PRQ = 148

< PRQ = 148o - 70o

= 78o