19.5cm2
15.0cm2
13.0cm2
9.3cm2
Correct answer is B
Perimeter of \(\bigtriangleup\) PQR = PQ + QR + PR
24cm = 6cm + 8cm = PR
24 = 14 + PR
PR = 24 - 14 = 10cm
Area of \(\bigtriangleup\) PRS = \(\frac{1}{2} \times 10 \times 3cm^3\)
= 15cm3