\(\frac{1}{12}\)
\(\frac{5}{12}\)
\(\frac{7}{12}\)
\(\frac{11}{12}\)
Correct answer is C
set = 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15
multiple of 3 = 6, 9, 12, 15
multiple of 4 = 4, 8, 12
Prob(multiple of 3 or 4) = Prob(multiple of 3) + pro(multiple of 4)
= \(\frac{4}{12} + \frac{3}{12} = \frac{7}{12}\)
Solve the equation; 3x - 2y = 7, x + 2y = -3
x = 1, y = -2
x = 1, y = 3
x = -2, y = -1
x = 4, y = -3
Correct answer is A
3x - 2y = 7; Solve by elimination method
x + 2y = -3
3x - 2y = 7.....(i)
-3x + 6y = -9.....(ii)
-8y = 16
y = \(\frac{16}{-8} = -2\)
Put y = -2 into equation (i); 3x - 2y = 7
3x - 2(-2) = 7
3x + 4 = 7
3x = 7 - 4
3x = 3
x = \(\frac{3}{3}\) = 1
Given that cos xo = \(\frac{1}{r}\), express tan x in terms of r
\(\frac{1}{\sqrt{r}}\)
\(\sqrt{r}\)
\(\sqrt{r^2 + 1}\)
\(\sqrt{r^2 - 1}\)
Correct answer is D
cos xo = \(\frac{1}{r}\); \(\sqrt{r^2 - 1}\)
By Pythagoras r2 = 12 + x2 - 1
x = \(\sqrt{r^2 - 1}\)
tan xo = \(\sqrt{r^2 - 1}\)
= \(\sqrt{r^2 - 1}\)
Solve for x in the equation; \(\frac{3}{5}\)(2x - 1) = \(\frac{1}{4}\)(5x - 3)
zero
1
2
3
Correct answer is D
\(\frac{3}{5}\)(2x - 1) = \(\frac{1}{4}\)(5x - 3)
\(\frac{6x}{5} - \frac{3}{5} = \frac{5x}{4} - \frac{3}{4}\)
\(\frac{6x}{5} - \frac{5x}{4} = \frac{3}{5} - \frac{3}{4}\)
\(\frac{24x - 25x}{20} = \frac{12 - 15}{20}\)
\(\frac{-x}{20} = \frac{-3}{20}\)
-20x = -60
x = \(\frac{-60}{-20}\)
x = 3
If N112.00 exchanges for D14.95, calculate the value of D1.00 in naira
0.13
7.49
8.00
13.00
Correct answer is B
D14.95 = N112.00
D1.00 = \(\frac{N112}{D14.95} \times\) D1.00
= 7.49