In the diagram, < WOX = 60^o, < YOE = 50^o and < OXY = 30^o. What is the bearing of x from y?

300^o

240^o

190^o

150^o

Correct answer is A

The bearing of x from y = 270^o + \(\theta\)

where \(\theta\) + 50^o = y

in \(\bigtriangleup\) OXY

O + X + Y = 180^o

Where O = 40^o + 30^o = 70^o

70^o + 30^o + y = 180^o

y + 100^o = 180^o

y = 180^o - 100^o = 30^o

\(\theta\) + 50^o = 80^o

80^o - 50^o = 30^o

The bearing of x from y = 270^o + 30^o = 300^o

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In the diagram, < WOX = 60o, < YOE = 50o and < OXY = 30o. What is the bearing of x from y?

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In the diagram, < WOX = 60^o, < YOE = 50^o and < OXY = 30^o. What is the bearing of x from y?